5 - 2w - 3w² = 0 can anyone answer this? please.?

5 - 2w - 3w² = 0
- ( 3w² + 2w - 5 ) = 0
- ( 3w + 5 )( w - 1 ) = 0

So,

3w + 5 = 0
w = -5/3

or

w - 1 = 0
w = 1

You should do these kinds of exercises yourself! Here are some tips:
1. Guess the roots. The roots usually are integers or 1/2,1/3,... - they are easy to guess. In this case, it's 1.
2. If you've found the roots - even one root, for example, 1: Obviously, when we factorize this equation, it must have (w-1) in order to give 1 as one root. (If one root is 1/2, there must be (2w-1).)
Then:
5 - 2w - 3w² = - ( 3w² + 2w - 5) = -[ 3w² - 3w + 5w - 5 ]
=-(w-1)(3w+5)

Therefore, this equation has two roots: 1 and -5/3.

3w² + 2w - 5 = 0
(3w + 5)(w - 1) = 0
w = - 5 / 3 , w = 1

5 - 2w - 3w^2 = 0
-3w^2 - 2w + 5 = 0
(-3w - 5)(w - 1) = 0

-3w - 5 = 0
-3w = 5
w = 5/-3
w = 1 2/-3

w - 1 = 0
w = 1

∴ w = 1 2/-3 , 1

3w²+2w-5= 0 (moved to the other side)
3w²-3w+5w-5=0
3w(w-1)+5(w-1)
(w-1)(3w+5)
w=1, -5/3
i think thats rigth lol

re arrange until u get w as the subject, then use ur calculator and put any numebr into w, and repeatly insert the answer u get into w, until the answer stops at a limit,

i am ownage