find the real root(s)
6/x-2 =x+3
(4/x+1)(3-x )=3
x^6+7x^3 -8=0
x-2= square root 2x-1
logx+log(x-3)=1
log (2x-10)-2logx =-1
9^x(x+1)=27^x+1
回答 (2)
✔ 最佳答案
As follows~
圖片參考:
http://i248.photobucket.com/albums/gg191/ncy_0916/log-1.jpg?t=1204731516
2008-03-05 23:40:32 補充:
log M + log N = log(MN)
log M - log N = log(M/N)
log10 = 1
2008-03-06 23:47:09 補充:
第4題的x ﹣2 = √(2x ﹣1)
x求到1 或 5
但個1要rejected,因為
L.H.S. = 1﹣2
= -1
R.H.S. = √(2 ﹣1)
= 1
即是L.H.S.≠R.H.S>
6/x-2 =x+3
(4/x+1)(3-x )=3
multiply x for both sides on above 2 questions
x^6+7x^3 -8=0
Try let x^3 = y, it becomes a quadratic equation
x-2= square root 2x-1
Take square on both sides
logx+log(x-3)=1
log(x^2-3x) = 1
x^2-3x=10
....
log (2x-10)-2logx =-1
try the method like the above question~
add oil!!
hope can help you to do the maths, except the last question..
參考: me
收錄日期: 2021-04-14 20:21:58
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