在數列{an}中,首項a1=0,且對任意正整數n,都有an+1=1/2(an+1),那麼,數列的通項an=? (需要步驟)
希望各高人可以幫忙!
數學通項式一問(等差/等比數列)
2008-03-04 7:26 am
回答 (2)
2008-03-06 3:02 am
數學通項式一問(等差/等比數列)
在數列{an}中,首項a1=0,且對任意正整數n,都有an+1=1/2(an+1),那麼,數列的通項an=? (需要步驟)
希望各高人可以幫忙!
2008-03-04 18:12:06 補充
The answer is 1-(1/2)^n-1....
2008-03-04 18:19:26 補充
在數列{a }中,首項a<1>=0,且對任意正整數n,都有a =1/2(a +1),那麼,數列的通項a =? (需要步驟)
<> <-----代表項數
題目有唔清楚地方......所以再打.....
2008-03-04 18:20:26 補充
The answer is 1-(1/2)^(n-1)....
在數列{an}中,首項a1=0,且對任意正整數n,都有an+1=1/2(an+1),那麼,數列的通項an=? (需要步驟)
希望各高人可以幫忙!
2008-03-04 18:12:06 補充
The answer is 1-(1/2)^n-1....
2008-03-04 18:19:26 補充
在數列{a }中,首項a<1>=0,且對任意正整數n,都有a =1/2(a +1),那麼,數列的通項a =? (需要步驟)
<> <-----代表項數
題目有唔清楚地方......所以再打.....
2008-03-04 18:20:26 補充
The answer is 1-(1/2)^(n-1)....
2008-03-04 7:44 am
The expression is not clear:
Whether it is A(n + 1) = 1/2 ( A(n) + 1)?
A(n + 1) = 1/(2 A(n) + 1)?
A(n) + 1 = 1/2 ( A(n + 1))?
A(n) + 1 = 1/[2 (A(n) + 1)]?
Whether it is A(n + 1) = 1/2 ( A(n) + 1)?
A(n + 1) = 1/(2 A(n) + 1)?
A(n) + 1 = 1/2 ( A(n + 1))?
A(n) + 1 = 1/[2 (A(n) + 1)]?
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