有關chem mixing solution問題

1.
你可以就咁睇,
當1M既10cm-3 HCl + 1M 既10 cm-3 既NaOH 混合後,
由於 HCl同NaOH 冇增加過, 所以number of mole 係冇變,
而volume就變左( 10 + 10), 既係之前既2倍,
molarity 自然係原來的一半,

你都可以計數,

number of mole = molarity x volume

以HCl為例,
number of mole before mixing = number of mole after mixing with NaOH
1 x 10 = molarity x (10 + 10)
molarity = 0.5M


2. 條式就係number of mole = molarity x volume

如要計molarity of HCl,
number of mole before mixing = number of mole after mixing with CH3COOH

1 x 10 = molarity x ( 10 + 20)
molarity = 0.3M

2008-03-03 23:11:09 補充：
其實HCl 同 NaOH 混合後會有neutralization= =

1. you have learnt MV(before)=MV (after)

no. of mole of HCL before= 1*10/1000

no of mole of HCL after= 1*20/1000

note that the total volume after mixed is changed, but no. of moles did not
change


2. no equation. the resulting solution is similar to the acidity of 10 cm-3
1M HCl