For two consecutive multiples of 3,5 times the larger number is not less than 2 times the smaller number plus 45. Find the minimum values of these two numbers.
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F.2 Maths [inequalities]
2008-03-03 2:01 am
回答 (1)
2008-03-03 2:56 am
✔ 最佳答案
let 3X be the smaller number, 3(X+1) is the larger number5 x3 (X+1) greater or equal to 2 x 3X +45
15X +15 greater or equal to 6X + 45
9X greater or equal to 30
X greater or equal to 10/3
therefore the minimum value of these two numbers are
3x 10/3 and 3x (1+10/3)
= 10 and 13
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