✔ 最佳答案
(This type of solution is out of the HKAL syllabus since 2007.)
Mole fraction of benzene in the solution = XB
Mole fraction of toluene in the solution = XT = 1 - XB
By Raoult's law:
Mole fraction of benzene in the vapour XB' = XBPBo = 95XB torr
Mole fraction of benzene in the vapour XT' = XTPTo = 28(1- XB) torr
XB' = XT'
95XB = 28(1 - XB)
XB = 0.228
Mole fraction of benzene in the solution XB = 0.228
Mole fraction of toluene in the solution XT = 1 - 0.228 = 0.772