3(4x + 2) = 6(2x + 1)?

So it does !!!
LHS = 12x + 6
RHS = 12x + 6

not defined

Are you trying to find out if this is a equal equation? If so, yes it is.
3(4x+2)=6(2x+1)
12x+6=12x+6
-6 -6 (from both sides)
12x=12x
Then subtract 12x on both side and it leaves you with 0 on boths sides. depending on the level of math would depend on how far to break it down but this is broke down as far as it will go.

distribute the 3 on the left side
and then the 6 on the right side

you get: 12x + 6 = 12x + 6

subtract 6 from the left side to the right side:

you get: 12x = 12x +0

subtract 12x from the left side to the right side:

you get: 0 = 0 as your answer!

3(4x + 2) = 6(2x + 1)
[3(4x + 2)]/3 = [6(2x + 1)]/3
4x + 2 = 2(2x + 1)
4x + 2 = 2*2x + 2*1
4x + 2 = 4x + 2
4x - 4x = 2 - 2
x = 0

are u trying to find out if its true?

divide the above by 3,

(4x+2)= 2(2x+1)

4x+2= 4x+2

the equation is correct

Use the distribution property on both sides:
12x+6=12x+6

Hmm. It appears that you have exactly the same thing on both sides. This means that any value you put into x will make the equation true. For your answer, say that all real values for x will satisfy the equation.

3(4x + 2) = 6(2x + 1)
LHS
= 3(4x + 2)
=3(2)(2x + 1)
=6(2x + 1)
= RHS

thus 3(4x+2) is equal to 6(2x+1)

alternatively, substitute x with a value eg.x=1
LHS
= 3(4(1) +2) = 3x6 =18
RHS
= 6(2(1) + 1) =6 x 3 =18
Since RHS = 18, LHS also = 18
thus 3(4x+2) is equal to 6(2x+1)