己知一個三角形的任何兩條邊的長度之和必定大於第三條邊的長度,,
若一個三角形的長度分別為5cm,6cm和x cm,其中x是一個整數,求x的所有可能值
5+6>x>6-5
11>x>1
x=2,3,4,5,6,7,8,9,10
但係我唔知條式點列出黎,,
唔該幫下我,,最好易明d=]
THZ^__________^
f.2Maths=]一元一次不等式
2008-02-29 3:48 am
回答 (2)
2008-02-29 7:31 am
✔ 最佳答案
己知一個三角形的任何兩條邊的長度之和必定大於第三條邊的長度,,=>5+6>x , 5+x>6 and 6+x>5
=>11>x , x>1 and x>-1
=>11>X>1// <---THAT 'S THE FINAL ANSWER!!
2008-02-29 8:08 pm
let 5+6> x, therefore 11>x (the side with 5cm and the side with 6 cm)
let 5+x>6, therefore x>1
we can not let 6+x>5 (x will be a negative number)
therefore , the answer is 11>x>1
therefore , x can be 2, 3, 4, 5, 6, 7, 8, 9 and 10
let 5+x>6, therefore x>1
we can not let 6+x>5 (x will be a negative number)
therefore , the answer is 11>x>1
therefore , x can be 2, 3, 4, 5, 6, 7, 8, 9 and 10
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