Maths Question, please help!!

2008-02-29 1:17 am
How to solve this equation? Find the two real solutions of:
x^6 - 198x^3 + 1 = 0

Thank you very much!!:)
更新1:

In answer 2, How to convert X = (99+(9802)^1/2))^1/3 to (8)^1/2 + 3 ???

回答 (2)

2008-02-29 2:17 am
✔ 最佳答案
As follows~As follows~As follows~As follows~As follows~As follows~As follows~As follows~As follows~As follows~As follows~As follows~As follows~As follows~As follows~As follows~As follows~As follows~As follows~As follows~As follows~As follows~

圖片參考:http://i204.photobucket.com/albums/bb125/jasonchan424/350.jpg


2008-03-05 00:08:40 補充:
Please refer to http://i204.photobucket.com/albums/bb125/jasonchan424/599.jpg
參考: ME, ME
2008-02-29 1:49 am
x^6 - 198x^3 + 1 = 0
(x)-198x+1=0
By applying the formula, you can get the values of x.
After then, take 1/3 root to the values, you can get the answers.
參考: me


收錄日期: 2021-04-24 09:11:24
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20080228000051KK01494

檢視 Wayback Machine 備份