5x+5y=1110
5x+3y=1050
用代入消元法計 thanks~ x]
f.2 maths 聯立二元一次方程''
2008-02-28 3:08 am
回答 (4)
2008-03-02 11:10 pm
5x+5y=1110........(1)
5x+3y=1050........(2)
(1)-(2)
5x+5y=1110
- ) 5x+3y=1050
----------------------
2y=60
y=30.........(3)
把(3)代入(2)
5x+3y=1050
5x+3(30)=1050
5x+90 =1050
5x=1050-90
5x=960
x=192
.
. . x=192,y=30
5x+3y=1050........(2)
(1)-(2)
5x+5y=1110
- ) 5x+3y=1050
----------------------
2y=60
y=30.........(3)
把(3)代入(2)
5x+3y=1050
5x+3(30)=1050
5x+90 =1050
5x=1050-90
5x=960
x=192
.
. . x=192,y=30
參考: me
2008-02-28 7:04 am
5x+5y=1110------(1)
5x+3y=1050------(2)
(1)-(2)
5x+5y-5x-3y = 1110-1050
2y= 60
y=30
將 y=30代入 (1)
5x+5(30)=1110
5x=960
x=192
5x+3y=1050------(2)
(1)-(2)
5x+5y-5x-3y = 1110-1050
2y= 60
y=30
將 y=30代入 (1)
5x+5(30)=1110
5x=960
x=192
參考: me
2008-02-28 3:16 am
5x+5y=1110...(1)
5x+3y=1050
5x=1050-3y...(2)
1050-3y+5y=1110...put(2)in(1)
2y=1110-1050
2y=60
y=30
5x+5y=1110
5x+5(30)=1110
x+30=222
x=192
2008-02-27 19:20:43 補充：
樓上回答者：Eileen計錯左=3=
5x+3y=1050
5x=1050-3y...(2)
1050-3y+5y=1110...put(2)in(1)
2y=1110-1050
2y=60
y=30
5x+5y=1110
5x+5(30)=1110
x+30=222
x=192
2008-02-27 19:20:43 補充：
樓上回答者：Eileen計錯左=3=
2008-02-28 3:11 am
5x + 5y = 1110
- 5x + 3y = 1050
------------------------
2y = 50
y = 25
5x + 3y = 1050
5x + 3 (25) = 1050
5x + 75 = 1050
5x = 1050 - 75
5x = 975
x = 975/ 5
x = 195
- 5x + 3y = 1050
------------------------
2y = 50
y = 25
5x + 3y = 1050
5x + 3 (25) = 1050
5x + 75 = 1050
5x = 1050 - 75
5x = 975
x = 975/ 5
x = 195
收錄日期: 2021-04-15 17:56:39
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https://hk.answers.yahoo.com/question/index?qid=20080227000051KK02217