MULTIPLY. 16x^4-81?
回答 (6)
2008-02-27 7:12 am
✔ 最佳答案
If you are looking for its factored form, that would be (2x-3)(2x+3)(4x^2+9)
2008-02-27 8:47 am
16x^4 - 81
= (4x^2 + 9)(4x^2 - 9)
= (4x^2 + 9)(4x^2 - 9)
2008-02-27 7:13 am
(4x^2+9)(2x+3)(2x-3)
2008-02-27 7:12 am
do u mean factorize??
(2x+3)(2x-3)(4x^2+9)
(2x+3)(2x-3)(4x^2+9)
2008-02-27 7:12 am
(4x^2+9)(4x^2-9)
2008-02-27 8:03 am
Factorise !!
(4x² - 9)(4x² + 9)
(2x - 3) (2x + 3) (4x² + 9)
(4x² - 9)(4x² + 9)
(2x - 3) (2x + 3) (4x² + 9)
收錄日期: 2021-05-01 10:08:54
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