2x^2 - 4x- 6= 0 pls solve the quadratic equation?

x ² - 2 x - 3 = 0
(x - 3)(x + 1) = 0
x = 3 , x = - 1

=2x^2-6x+2x-6=0
2x(x-3)+2(x-3)=0
(2x+2)(x-3)=0
2(x+1)(x-3)=0
(x+1)(x-3)=0
x+1=0 or (x-3)=0
x=(-1) or x=3

(2x+2)(x-3)=0
2x+2 = 0; 2x = -2; x = -1
x-3=0; x=3

answer: x = -1,3

2x^2 - 4x - 6 = 0
(2x + 2)(x - 3) = 0

2x + 2 = 0
2x = -2
x = -2/2
x = -1

x - 3 = 0
x = 3

∴ x = -1 , x = 3

2x^2 - 4x- 6= 0
2x^2 - 6x+ 2x - 6= 0
(2x + 2)(x - 3)= 0
x=-1 or x=3