更新1:
唔可以只答answer
一條多項式
回答 (3)
2008-02-24 2:28 am
✔ 最佳答案
(x^2-x+2)(x^2+x-2)-(x-2)^2=x^4+x^3-2x^2-x^3-x^2+2x+2x^2+2x-4-x^2+4x-4
=x^4-2x^2+8x-8
很詳細了....你咁答拿足分...
參考: 自己
2008-02-24 2:31 am
( X^2-X+2)(X^2+X-2)-(X-2)^2
=(X^2-(X-2))(X^2+(X-2))-(X-2)^2
=(X^2)^2-(X-2)^2-(X-2)^2 <-----A^2-B^2=(A+B)(A-B)
=(X^4)-2(X-2)
2008-02-23 18:34:05 補充：
最尾唔係(X^4)-2(X-2) 係(x^4)-2(x-2)^2=x^4-2(x^2-4x-4)=x^4-2x^2-8x-8
2008-02-23 18:35:42 補充：
咁計就唔洗左乘加乘咁煩~唔會咁易乘少左
=(X^2-(X-2))(X^2+(X-2))-(X-2)^2
=(X^2)^2-(X-2)^2-(X-2)^2 <-----A^2-B^2=(A+B)(A-B)
=(X^4)-2(X-2)
2008-02-23 18:34:05 補充：
最尾唔係(X^4)-2(X-2) 係(x^4)-2(x-2)^2=x^4-2(x^2-4x-4)=x^4-2x^2-8x-8
2008-02-23 18:35:42 補充：
咁計就唔洗左乘加乘咁煩~唔會咁易乘少左
參考: 自己計~唔知有冇錯
2008-02-24 2:31 am
(x2次-x+2)(x2次+x-2)-(x-2)2次
=(x+2)(x^3-2)-(x^2-2^2)
=(x+2)(x^3-2)-(x^2-4)
=(x^3+1+2*-2)-(x^2-4)
=x^4+(-4)-(x^2-4)
=x^4-4-(x^2-4)
=x^4-2-4+4
=x^2
=(x+2)(x^3-2)-(x^2-2^2)
=(x+2)(x^3-2)-(x^2-4)
=(x^3+1+2*-2)-(x^2-4)
=x^4+(-4)-(x^2-4)
=x^4-4-(x^2-4)
=x^4-2-4+4
=x^2
收錄日期: 2021-04-24 09:57:08
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20080223000051KK03296