In feet, what are the area and perimeter of the classroom...L=312inches and W=192 inches?

L = 312inches = (312/12) feet = 26 feet
W = 192inches = (192/12) feet = 16 feet

Area = L*W = 416 sq.ft.
Perimeter = 2*(L+W) = 84 ft.

312 " = 312 / 12 ft = 26 ft
192 " = 192 / 12 ft = 16 ft

A = 26 x 16 ft ²
A = 416 ft ²

P = 2 (26 + 16) ft
P = 84 ft

first convert the inches into feet. there are 12 inches in a foot, so the length=312/12=26 feet. the width is 192/12=16 feet. area is length times width, so 26 times 16=416 feet. perimeter is 2L + 2W, so (2)(26) + (2)(16)=52 + 32=84 feet.

1 foot = 12 inches
1 inch = 1/12 foot

(312 + 192)/12 x 2
= 504/12 x 2
= 42 x 2
= 84 feet

P = 2(L+W)
P= 2 (312+192)
P = 2 x 504
P= 1008 inches
P= 1008/12
P= 84 feet

A = L x W
A = 312 x 192 sq. inche
A = (312 x 192 /12 x 12) sq. feet
A = 416 sq. ft

L=312" = 26'
W=192"=16'

Area =L*W=26*16 sq.feet = 416 sq.feet

Perimeter =2(L+W)=2(26+16) = 84 feet

area= 84 square feet
perimeter=84 feet