Inequalities

2008-02-21 5:53 am
Solve 3/(x-2)>1????

回答 (3)

2008-02-21 5:58 am
✔ 最佳答案
3/(x-2)>1
[ 3/(x-2)](x-2)^2>(x-2)^2
3(x-2)>(x-2)^2
3x-6>x^2-4x+4
x^2-7x+10<0
(x-2)(x-5)<0
2<x<5
2008-02-21 8:10 am
3/(x - 2) &gt; 1
3/(x - 2) * (x - 2)^2 &gt; (x - 2)^2
3(x - 2) &gt; (x - 2)^2
3(x - 2) - (x - 2)^2 &gt; 0
(x - 2)(3 - x + 2) &gt; 0
(x - 2)(-x + 5) &gt; 0
(x - 2)(x - 5) &lt; 0
2 &lt; x &lt; 5

開首跟第一位相同
但如第二位所說為免出錯
不 expend (x - 2)^2 為好
直接 fact

2008-02-21 00:11:35 補充:
亦無需分case
2008-02-21 5:59 am
3/(x-2)&gt;1
3/(x-2) - 1 &gt;0
[3-(x-2)] / (x-2) &gt; 0
(5-x)(x-2) &gt; 0 as (x-2)^2 &gt;=0
(x-5)(x-2)&lt;0
2&lt;5

2008-02-20 21:59:47 補充:
2

2008-02-20 22:02:36 補充:
typing mistake ~2&lt; x &lt; 5樓上做法同出一徹..不過多此一舉..因為最後要fact番倒不如一早通分母會比較快同減少運術錯誤既機會
參考: myself


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