F.2數學題1條 (10分!!!!!)
回答 (2)
2008-02-21 2:18 am
✔ 最佳答案
(a-2b)²+(2a-b)(2b-a)=(a²-4ab+4b²)+(4ab-2a²-2b²+ab)
=a²-4ab+4b²+4ab-2a²-2b²+ab
=-a²+2b²+ab
=a²-2b²-ab --->le步唔知要唔要
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應該你correct
2008-02-20 18:19:22 補充：
應該係correct
參考: me
2008-02-21 12:21 am
(a - 2b) [(a -2b) - (2a -b)]
= (a - 2b) (a- 2a -2b + b)
= (a - 2b) (-a - b)
= (a+b) (2b - a)
= (a - 2b) (a- 2a -2b + b)
= (a - 2b) (-a - b)
= (a+b) (2b - a)
收錄日期: 2021-04-13 15:11:48
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