MATH~~~~~~F.2
回答 (2)
2008-02-19 3:41 am
✔ 最佳答案
= 3^9n / 3^2n x 3^2n=3^(9n-2n-2n)
=3^5n
2008-02-19 3:43 am
27^3n/3^2n*9^n
你個問題打漏左少少野bo~~
可以係(27^3n/3^2n)*9^n
(27^3n/3^2n)*9^n
=(3^9n/3^2n)*3^2n
=3^9n-2n+3n
=3^10n
都可以係27^3n/(3^2n*9^n)
27^3n/(3^2n*9^n)
=3^9n/(3^2n*3^2n)
=3^9n-2n-2n
=3^5n
你個問題打漏左少少野bo~~
可以係(27^3n/3^2n)*9^n
(27^3n/3^2n)*9^n
=(3^9n/3^2n)*3^2n
=3^9n-2n+3n
=3^10n
都可以係27^3n/(3^2n*9^n)
27^3n/(3^2n*9^n)
=3^9n/(3^2n*3^2n)
=3^9n-2n-2n
=3^5n
收錄日期: 2021-04-29 20:24:43
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