simple logarithms

2008-02-18 8:07 am
is it possible to solve
1000(1.06)^x = 100x + 1000
where ^ = raise to a power of
Find x with step

回答 (1)

2008-02-18 2:19 pm
✔ 最佳答案
1000(1.06)^x = 100x + 1000
10(1.06)^x = x + 10
log10 + xlog1.06 = log(x+10)
1 + xlog1.06 = log(x+10)
用 graph 既方法, plot
y = 1 + xlog1.06 直線
y = log(x+10) < log 圖, 只係向左平移 10 個單位 >
交點個 x 坐標就係答案
-------------------------------------------------------------------------------
如果你識, 可以用 numerical 既方法
bisection, 或者其他, 好多方法
-------------------------------------------------------------------------------
但係你話解 x 係乜, 我睇就唔係咁得

2008-02-18 06:20:00 補充:
要唔要補習,有我, 囉 A, 無難度


收錄日期: 2021-04-19 23:54:47
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20080218000051KK00032

檢視 Wayback Machine 備份