Solve. x^2 + 8x – 20 = 0?

Hi,

x² + 8x - 20 = 0
(x + 10)(x - 2) = 0
x = -10 or x = 2 <== ANSWERS

I hope that helps!! :-)

(x + 10)(x - 2) = 0
x = - 10 , x = 2

x^2+8x-20=0
(x+10)(x-2)=0
(x+10)=0
x= -10
if (x-2) =0
x= 2

Therefore x= -10, 2

a million.) x^(2)-8x-20=0 in this issue 2*-10=-20 and a couple of-10=-8, so insert 2 through fact the proper hand term of one factor and -10 through fact the proper-hand term of the different factor. (x+2)(x-10)=0 Set each and every of the factors of the left-hand factor of the equation equivalent to 0. x+2=0_x-10=0 on account that 2 would not incorporate the variable to sparkling up for, pass it to the proper-hand factor of the equation with the aid of subtracting 2 from the two factors. x=-2_x-10=0 Set each and every of the factors of the left-hand factor of the equation equivalent to 0. x=-2_x-10=0 on account that -10 would not incorporate the variable to sparkling up for, pass it to the proper-hand factor of the equation with the aid of including 10 to the two factors. x=-2_x=10 the great answer is the set of the guy suggestions. x=-2,10 2.) 8x^(2)=24x on account that 24x includes the variable to sparkling up for, pass it to the left-hand factor of the equation with the aid of subtracting 24x from the two factors. 8x^(2)-24x=0 factor out the GCF of 8x from each and every term interior the polynomial. 8x(x)+8x(-3)=0 factor out the GCF of 8x from 8x^(2)-24x. 8x(x-3)=0 Set the only term factor on the left-hand factor of the equation equivalent to 0. 8x=0 Divide each and every term interior the equation with the aid of 8. (8x)/(8)=(0)/(8) Simplify the left-hand factor of the equation with the aid of canceling the effort-free factors. x=(0)/(8) 0 divided with the aid of any huge sort or variable is 0. x=0 Set each and every of the factors of the left-hand factor of the equation equivalent to 0. x-3=0 on account that -3 would not incorporate the variable to sparkling up for, pass it to the proper-hand factor of the equation with the aid of including 3 to the two factors. x=3 the great answer is the set of the guy suggestions. x=0,3

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-10 and 2
Use the graph of it and substitution!

x^2 + 8x - 20 = 0
(x + 10)(x - 2) = 0

x + 10 = 0
x = -10

x - 2 = 0
x = 2

∴ x = -10 or 2

x^2+8x-20=0
add 20
x^2+8x=20
add 8x
x^2=20+8x
divide by x
x=20+8
simplify that so...x=28