中一方程式
h-[2(h-1)+10]=5(h-34)
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回答 (6)
✔ 最佳答案
h-[2(h-1)+10]=5(h-34)
h-[2h-2+10]=5h-170
h-2h+2-10=5h-170
-h-8=5h-170
6h=162
h=27
參考: 自己
h-[2(h-1)+10]=5(h-34)
h-(2h-2+10) = 5h - 170
h -2h +2 -10 = 5h -170
-8 + 170 = 5h +h
6h = 162
h = 27
h-[2(h-1)+10]=5(h-34)
h-(2h-2+10)=5h-170
h-2h-8=5h-170
-h-5h=-170+8
-6h=-162
h=27
h-[2(h-1)+10]=5(h-34)
h-(2h-2+10) = 5h-170
h-2h+2-10 = 5h-170
-6h = -162
h = 27
h-[2(h-1)+10]=5(h-34)
h-(2h-2+10)=5h-170
-h-8=5h-170
6h=162
h=27
h-[2h-2+10] = 5h-170
h-2h+2-10 = 5h-170
h-2h-5h = 10-2-170
-6h = -162
h = 27
收錄日期: 2021-04-13 15:10:31
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