中一方程式

2008-02-17 11:08 pm
h-[2(h-1)+10]=5(h-34)

求步驟&答案
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回答 (6)

2008-02-17 11:15 pm
✔ 最佳答案
h-[2(h-1)+10]=5(h-34)
h-[2h-2+10]=5h-170
h-2h+2-10=5h-170
-h-8=5h-170
6h=162
h=27
參考: 自己
2008-02-19 11:40 pm
h-[2(h-1)+10]=5(h-34)

h-(2h-2+10) = 5h - 170
h -2h +2 -10 = 5h -170
-8 + 170 = 5h +h
6h = 162
h = 27
2008-02-18 12:50 am
 h-[2(h-1)+10]=5(h-34)
  h-(2h-2+10)=5h-170
     h-2h-8=5h-170
      -h-5h=-170+8
       -6h=-162
        h=27
2008-02-18 12:00 am
h-[2(h-1)+10]=5(h-34)


h-(2h-2+10) = 5h-170

h-2h+2-10 = 5h-170

-6h = -162
h = 27
2008-02-17 11:17 pm
h-[2(h-1)+10]=5(h-34)
h-(2h-2+10)=5h-170
-h-8=5h-170
6h=162
h=27
2008-02-17 11:14 pm
h-[2h-2+10] = 5h-170

h-2h+2-10 = 5h-170

h-2h-5h = 10-2-170

-6h = -162

h = 27


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