http://i181.photobucket.com/albums/x133/kissme1101/011.jpg
In the figure ,EGHF is a stright line.
Prove that AB//CD
∠AGH係140度
∠DHF係40度
問一題數學題
2008-02-17 1:52 am
回答 (2)
2008-02-17 2:06 am
✔ 最佳答案
∠DHE=180°-40°〔∠s at st. line〕
=140°
∠EGB
=180°-140°〔∠s at st. line〕
=40°
∵∠AGB=∠AGD
∴AB//CD
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參考: my brain
2008-02-17 1:59 am
∠BGH+140 度 =180度 (adj. ∠s on st. line)
since ∠BGH=∠DHF
therefore AB//CD (corr. ∠s equal)
2008-02-16 18:00:57 補充：
∠BGH 140 度 =180度 (adj. ∠s on st. line)∠BGH=40度since ∠BGH=∠DHF=40度therefore AB//CD (corr. ∠s equal) 呢個詳細D.
since ∠BGH=∠DHF
therefore AB//CD (corr. ∠s equal)
2008-02-16 18:00:57 補充：
∠BGH 140 度 =180度 (adj. ∠s on st. line)∠BGH=40度since ∠BGH=∠DHF=40度therefore AB//CD (corr. ∠s equal) 呢個詳細D.
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