Patrick spends$36to buy some apples and oranges.Each apple and orange cost$2and$2.5respectively.The number of apples that he buys is 9 more than that of oranges.How many apples and oranges does he buy?
Just use Simultaneous Linear Equations
Use the method of elimination....thank you
F.2Maths,help
2008-02-17 1:00 am
回答 (2)
2008-02-17 1:39 am
✔ 最佳答案
let x be the number of apple and y be that of orange2x+2.5y=36 -----(1)
x-y=9 -----(2)
(2)*2
2x-2y=18 -----(3)
(1)-(3)
2x+2.5y-2x+2y=36-18
4.5y=18
y=4
sub y = 4 into (2)
x-4=9
x=13
therefore he buy 13 apples and 4 oranges
參考: me
2008-02-17 1:45 am
let x : number of apples
let y : number of oranges
y < x+9
2x+2.5y=36
2x+2.5(x+9)=36
2x+2.5x+22.5=36
4.5x+22.5-22.5=36-22.5
4.5x / 4.5 =13.5 / 4.5
x=3
y < x+9
y=x+9
y=3+9
y=12
y<12
__________________________________
可能唔岩 ==
let y : number of oranges
y < x+9
2x+2.5y=36
2x+2.5(x+9)=36
2x+2.5x+22.5=36
4.5x+22.5-22.5=36-22.5
4.5x / 4.5 =13.5 / 4.5
x=3
y < x+9
y=x+9
y=3+9
y=12
y<12
__________________________________
可能唔岩 ==
收錄日期: 2021-04-13 15:09:42
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