1.) z(1+20分之7)=540
z=?
2. ) m(2-4分之3)=31有4分之1
m=?
2題簡易方程,只要答案
2008-02-16 8:20 pm
回答 (2)
2008-02-16 8:31 pm
1. z(1+7/20)=540
... z(27/20)=540
... 27z = 540*20
... z = 540*20/27
z = 400
2. m = 25
... z(27/20)=540
... 27z = 540*20
... z = 540*20/27
z = 400
2. m = 25
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