1)1/s+1/t =2t (Change subject to s)
2) a)x=0 Graphic
b)y=x^2 Graphic
c)x+2y-1=0 Graphic
d)x/2-y/3=1 Graphic
Which Graphics is not a st. line?
3)h=2/h-1/k (Change subject to k)(Need to hv step!!)
4)1^3,2^3,3^3,4^3
What is the term of no.11?(Need to hv step!!)
5)abc為直角三角形。角b=90,BC = x,AC=x+2 及ab=10 Find X (Need to hv step!!)
Maths F.2(5題)(10點!!)
2008-02-16 8:17 am
回答 (2)
2008-02-16 8:48 am
✔ 最佳答案
1) 1/s + 1/t = 2t通分母
t/st + s/st = 2t
t + s = 2t(st)
t = 2t(st)-s
t = s(2t^2-1)
s = t/(2t^2-1)
2) b) y=x^2
因為二次方不會是直線
3) h = 2/h - 1/k
通分母
h = 2k/hk - h/hk
h(hk) = 2k - h
h = 2k - h^2k
h = k(2 - h^2)
k = h/(2 - h^2)
4) First team is 1^3
Second team is 2^3
Third team is 3^3
term of no.11 is 11^3 = 1331
5) 因為 b = 90
由畢氏定理
10^2 + x^2 = (x+2)^2
100 + x^2 = x^2 + 4x + 4
4x = 96
x = 24
2008-02-17 2:46 am
1) 1/s + 1/t = 2t
1/s= 2t-1/t
1/s= 1.5t
1= 1.5t/s
s=1/1.5t
2) b) y=x^2
3) h = 2/h - 1/k
1/k= 2/h-h
1/k=2/h-h^2/h
1/k= 2-h^2/h
k=h/2-h^2
4) term of no.11
= n^3
= 11^3
= 1331
5) 因為abc=直角三角形
由畢氏定理:a^2+b^2=(a+b)^2
10^2 + x^2 = (x+2)^2
100 + x^2 = x^2 + 4x + 4
4x = 96
x = 24
1/s= 2t-1/t
1/s= 1.5t
1= 1.5t/s
s=1/1.5t
2) b) y=x^2
3) h = 2/h - 1/k
1/k= 2/h-h
1/k=2/h-h^2/h
1/k= 2-h^2/h
k=h/2-h^2
4) term of no.11
= n^3
= 11^3
= 1331
5) 因為abc=直角三角形
由畢氏定理:a^2+b^2=(a+b)^2
10^2 + x^2 = (x+2)^2
100 + x^2 = x^2 + 4x + 4
4x = 96
x = 24
參考: me
收錄日期: 2021-04-13 15:09:14
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