math!!!!!!!!!!!!!help!!!!!!!!!!!!!!!!!!!!!

A, B 的中點是 (3,3)

設 (a,a) 為△ＡＢＣ的內心的坐標 ( 0<3 )

(a,a) 與 (3,3) 間之距離 亦是 a
(a - 3)^2 + (a - 3)^2 = a^2
a^2 - 12a + 18 = 0
a = 6 - 3sqrt(2) (另一解大於 3)

所以 △ＡＢＣ的內心的坐標為 ( 6-3sqrt(2), 6-3sqrt(2) )