數學唔識呀...help←"送(30分)
2008-02-15 2:14 am
1.把公式ax-b+c=0的主項變轉為x。
2.把公式d-e=fx-cx的主項變轉為x。
3.把公式v=u+at的主項變轉為a。
4..把公式ax+c=dx-b的主項變轉為x。
5.如果p=100和v=5，求m的值。
6.如果R=100、K=60和 l =20,求A的值。
回答 (7)
2008-02-16 7:12 pm
1)ax-b+c=0
ax=b-c
x=(b-c)/a
2)d-e=fx-cx
d-e=x(f-c)
x=(d-e)/(f-c)
3)v=u+at
at=v-u
a=(v-u)/t
4)ax+c=dx-b
c+b=dx-ax
c+b=x(d-a)
x=(c+b)/(d-a)
ax=b-c
x=(b-c)/a
2)d-e=fx-cx
d-e=x(f-c)
x=(d-e)/(f-c)
3)v=u+at
at=v-u
a=(v-u)/t
4)ax+c=dx-b
c+b=dx-ax
c+b=x(d-a)
x=(c+b)/(d-a)
2008-02-15 2:53 am
1 ax-b+c=0
ax=b-c because move to the another side + change to-
x=(b-c)/a becases move to the otherside x change to /
2 d-e=fx-cx
d-e=x(f-c) because x(f-c)=fx-cx
(d-e)/(f-c)=x
x=(d-e)/(f-c)
3 v=u+at
v-u=at because +u move to the other side will be -u
(v-u)/t=a because when axt move the t to another side it will change to /t
a=(v-u)/t
4 ax+c=dx-b
ax-dx=-b-c
x(a-d)=-b-c
x=(-b-c)/(a-d)
5 because there are two unknow and you have no question so i can anser you
6 because there are two unknow and you have no question so i can anser you
ax=b-c because move to the another side + change to-
x=(b-c)/a becases move to the otherside x change to /
2 d-e=fx-cx
d-e=x(f-c) because x(f-c)=fx-cx
(d-e)/(f-c)=x
x=(d-e)/(f-c)
3 v=u+at
v-u=at because +u move to the other side will be -u
(v-u)/t=a because when axt move the t to another side it will change to /t
a=(v-u)/t
4 ax+c=dx-b
ax-dx=-b-c
x(a-d)=-b-c
x=(-b-c)/(a-d)
5 because there are two unknow and you have no question so i can anser you
6 because there are two unknow and you have no question so i can anser you
參考: me
2008-02-15 2:34 am
1)ax-b+c=0
ax=b-c
x=(b-c)/a
2)d-e=fx-cx
d-e=x(f-c)
x=(d-e)/(f-c)
3)v=u+at
at=v-u
a=(v-u)/t
4)ax+c=dx-b
c+b=dx-ax
c+b=x(d-a)
x=(c+b)/(d-a)
5)如果p=100和v=5(??)
6)如果R=100、K=60和 l =20(??)
ax=b-c
x=(b-c)/a
2)d-e=fx-cx
d-e=x(f-c)
x=(d-e)/(f-c)
3)v=u+at
at=v-u
a=(v-u)/t
4)ax+c=dx-b
c+b=dx-ax
c+b=x(d-a)
x=(c+b)/(d-a)
5)如果p=100和v=5(??)
6)如果R=100、K=60和 l =20(??)
2008-02-15 2:31 am
1.ax-b+c=0
ax-b =-c
ax=-c+b
x=(-c+b)
—
a
2.d-e=fx-cx
d-e=x(f-c)
x= (d-e)
—
(f-c)
3.v=u+at
v-u=at
a= v-u
—
t
4.ax+c=dx-b
ax-dx=-b-c
x(a-d)=-b-c
x=-(b-c)
—
-(d-a)
x=(b-c)
—
(d-a)
Q5、6不知你問咩？
ax-b =-c
ax=-c+b
x=(-c+b)
—
a
2.d-e=fx-cx
d-e=x(f-c)
x= (d-e)
—
(f-c)
3.v=u+at
v-u=at
a= v-u
—
t
4.ax+c=dx-b
ax-dx=-b-c
x(a-d)=-b-c
x=-(b-c)
—
-(d-a)
x=(b-c)
—
(d-a)
Q5、6不知你問咩？
2008-02-15 2:28 am
1.ax=b-c
x=(b-c)/a
2.d-e=x(f-c)
x=(d-e)/(f-c)
3.at=v-u
a=(v-u)/t
4.dx-ax=b+c
x(d-a)=b+c
x=(b+c)/(d-a)
5同6你好似打少左d野...你check下我再答...
x=(b-c)/a
2.d-e=x(f-c)
x=(d-e)/(f-c)
3.at=v-u
a=(v-u)/t
4.dx-ax=b+c
x(d-a)=b+c
x=(b+c)/(d-a)
5同6你好似打少左d野...你check下我再答...
參考: 我自己
2008-02-15 2:26 am
1.ax-b+c=0
ax=b-c
x=(b-c)/a
2.d-e=fx-cx
d-e=x(f-c)
x=(d-e)/(f-c)
3.v=u+at
v-u=at
a=(v-u)/t
4.ax+c=dx-b
dx-ax=b-c
x(d-a)=b-c
x=(b-c)/(d-a)
5同6無式，計唔到
ax=b-c
x=(b-c)/a
2.d-e=fx-cx
d-e=x(f-c)
x=(d-e)/(f-c)
3.v=u+at
v-u=at
a=(v-u)/t
4.ax+c=dx-b
dx-ax=b-c
x(d-a)=b-c
x=(b-c)/(d-a)
5同6無式，計唔到
2008-02-15 2:24 am
1.)ax-b+c=0
ax=b-c
x=(b-c)/a
2.)d-e=fx-cx
d-e=x(f-c)
x=(d-e)/(f-c)
3.)v=u+at
v-u=at
a=(v-u)/t
4.)ax+c=dx-b
ax-dx=-b-c
x(a-d)=-b-c
x=(-b-c)/(a-d) [or x= (b+c)/d-a)]
唔知你5~6題既問題
所以做唔到...
ax=b-c
x=(b-c)/a
2.)d-e=fx-cx
d-e=x(f-c)
x=(d-e)/(f-c)
3.)v=u+at
v-u=at
a=(v-u)/t
4.)ax+c=dx-b
ax-dx=-b-c
x(a-d)=-b-c
x=(-b-c)/(a-d) [or x= (b+c)/d-a)]
唔知你5~6題既問題
所以做唔到...
參考: 自己計
收錄日期: 2021-04-25 22:11:09
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20080214000051KK03256