有2條唔記得左點計..
1. (5X^2-x)(-2x)
2.(4x+3y)(x-2y)
數學2條..[展開]..
2008-02-13 5:33 am
回答 (2)
2008-02-13 5:45 am
✔ 最佳答案
1.(5X^2-x)(-2x)= -10X^3+2X^2
2.(4x+3y)(x-2y)
= 4x^2-8xy+3xy-6y^2
=4X^2-5xy-6y^2
希望幫到你啦
參考: ME
2008-02-13 6:06 am
1.(5X^2-x)(-2x)
= -10X^3+2X^2
2.(4x+3y)(x-2y)
=4x(x-2y)+3y(x-2y)
= 4x^2-8xy+3xy-6y^2
=4X^2-5xy-6y^2
= -10X^3+2X^2
2.(4x+3y)(x-2y)
=4x(x-2y)+3y(x-2y)
= 4x^2-8xy+3xy-6y^2
=4X^2-5xy-6y^2
參考: me
收錄日期: 2021-04-19 00:32:54
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20080212000051KK04237