how to factorize?
回答 (2)
2008-02-13 2:22 am
✔ 最佳答案
4-20(c-3d)+25(c-3d)^2= (2)^2 - 2(2)(5)(c-3d) +[5(c-3d)]^2
=[4-5(c-3d)]^2
=(15d-5c+4)^2//
2008-02-12 19:45:39 補充：
=(15d-5c+2)^2//
2008-02-12 19:46:06 補充：
=[2-5(c-3d)]^2=(15d-5c+2)^2//
2008-02-14 5:32 am
4 - 20(c-3d) + 25(c-3d)^2
= 2^2 + 2(2)(5)(c - 3d) + (5(c - 3d))^2
=(2 + 5(c - 3d))^2
=(2 + 5c - 15d)^2
= 2^2 + 2(2)(5)(c - 3d) + (5(c - 3d))^2
=(2 + 5(c - 3d))^2
=(2 + 5c - 15d)^2
收錄日期: 2021-04-13 15:07:51
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20080212000051KK03156