F1 .Maths

2. It is knoen that 6-digits number A1527B is multiple of 4,and the remainder is 5 when it is divided by 11.Find the value of A +B .
Since A1527B is multiple of 4
7B is multiple of 6
B=6
remainder is 5 when it is divided by 11
A-1+5-2+7-1=0 (mod11)
A=3
A+B=9
3Find the smallest prime number that divides the number3的13次方+5的31次方
3^13=1 (mod2)
5^31=1 (mod2)
So 3^13+5^31=0 (mod2)
the smallest prime number that divides the number3的13次方+5的31次方 is 2
A=1


2008-02-12 15:27:52 補充：
Correction 7B is multiple of 4A=1 多餘了

2008-02-12 15:34:30 補充：
我覺得第一題好似只可以撞﹐但撞的話就不是數學。

1. M and n can be 1and 6 respectively. Total cost is $12936, if you purchase 147 tickets.

2. A and B can be 3 and 6 respectively, the avilable number may be 315276.

3. sorry...

2008-02-12 15:20:17 補充：
sorry is for Q1the answer should be $147 for each ticket

吾識 .
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