6x2+19x+15?
2008-02-11 5:41 pm
I have no idea on how to get it passed this i really dont think it can be solved
回答 (9)
2008-02-11 5:44 pm
✔ 最佳答案
=(2x+3)(3x+5)And no, you can't use the quadratic formula.
The formula is only to be used when
ax^2+bx+c=0... ie it must be a 2 sided equation.
2008-02-11 5:46 pm
6x^2 + 19x + 15
= (2x + 3)(3x + 5)
= (2x + 3)(3x + 5)
2008-02-11 5:43 pm
the answer is (3x+5)(2x+3)
i factored, you could use the quadratic formula
i factored, you could use the quadratic formula
2016-12-11 8:03 pm
You seem on the variables and combine like words. in case you have 'kx' (the place ok is a persevering with), you combine all words that resemble 'kx'. in case you have 'ok' (which might merely be a single extensive type, which includes 8), you combine each and all of the 'ok' words. in case you had 'kx^2' (the place ^2 ability "squared"), you will possibly combine all 'kx^2' words. i will answer the 1st of the addition, and the 1st of the subtraction. Subtraction: (14x + 5) + (10x + 5) factor the constructive sign into the 2d term =14x + 5 + 10x + 5 combine like words =24x + 10 Addition: (6x + 14) - (9x + 5) right here, distribute the unfavourable sign into the 2d term =6x + 14 - 9x - 5 Now, combine like words. = -3x + 9
2008-02-11 5:54 pm
I assume that you meant to write
6x^2 + 19x - 15 =0
Using the quadratic formula with a = 6, b = 19 and c=-15
[-19 plus or minus sqrt(19*19 +4*6*15)]/12
[-19 plus or minus sqrt(721)]/12
6x^2 + 19x - 15 =0
Using the quadratic formula with a = 6, b = 19 and c=-15
[-19 plus or minus sqrt(19*19 +4*6*15)]/12
[-19 plus or minus sqrt(721)]/12
參考: Longtime college math teacher
2008-02-11 5:52 pm
6x^2+19x+15
6x^2+10x+9x+15
2x(3x+5)+3(3x+5)
(3x+5)(2x+3)
6x^2+10x+9x+15
2x(3x+5)+3(3x+5)
(3x+5)(2x+3)
2008-02-11 5:50 pm
6x² + 19x + 15
6x² + 10 x + 9x + 15
2x(3x + 5) + 3(3x + 5)
(3x + 5)(2x + 3)
6x² + 10 x + 9x + 15
2x(3x + 5) + 3(3x + 5)
(3x + 5)(2x + 3)
2008-02-11 5:50 pm
This equation is of form ax^2+bx+c
a = 6 b = 19 c = 15
x=[-b+/-sqrt(b^2-4ac)]/2a]
x=[-19 +/-sqrt(19^2-4(6)(15)]/(2)(6)
discriminant is b^2-4ac =1
x=[-19 +√(1)] / (2)(6)
x=[-19 -√(1)] / (2)(6)
x=[-19+1] / 12
x=[-19-1] / 12
The roots are -1.5 and -1.667
a = 6 b = 19 c = 15
x=[-b+/-sqrt(b^2-4ac)]/2a]
x=[-19 +/-sqrt(19^2-4(6)(15)]/(2)(6)
discriminant is b^2-4ac =1
x=[-19 +√(1)] / (2)(6)
x=[-19 -√(1)] / (2)(6)
x=[-19+1] / 12
x=[-19-1] / 12
The roots are -1.5 and -1.667
2008-02-11 5:46 pm
The above answer is correct!
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