Maths Question

6(a+1)^2+4(a+1)
=6(a^2+2a+1)+4a+4
=6a^2+12a+4a+6+4
=6a^2+16a+10
=6a^2+6a+10a+10
=(6a+10)(a+1)

2008-02-10 22:47:52 補充：
=2(3a 5)(a 1)

6(a+1)²+4(a+1)
=6(a+1)x(a+1)+4x(a+1) ---ps:a²=(a+1)(a+1)
=[6(a+1)+4]x(a+1) ---ps:兩邊都有(a+1),用乘法分配性則
=(6a+6+4)(a+1) ---ps:6(a+1)=6a+6
=(6a+10)(a+1) ---ps:這些題目通常佔三分,有一分就考你最後懂不懂抽2出來
=2(3a+5)(a+1) ---ps:完成,拿足三分

6(a+1)^2+4(a+1)
= 2(a+1) [3(a+1) + 2]
= 2(a+1) (3a +5)