Find the general solution of the following equation.
sin 2x - 2 sin x - cos x + 1 = 0
F.4 A.Maths
2008-02-11 1:47 am
回答 (3)
2008-02-11 1:55 am
2008-02-11 1:56 am
sin 2x - 2 sin x - cos x + 1 = 0
2sin x cos x - 2 sin x - cos x + 1 = 0
2sin x ( cos x - 1 ) - ( cos x - 1 ) = 0
( 2sin x - 1 ) ( cos x - 1 ) = 0
sin x =1 / 2 or cos x = 1
....
x = 咩野 , 自己計到啦 !
2sin x cos x - 2 sin x - cos x + 1 = 0
2sin x ( cos x - 1 ) - ( cos x - 1 ) = 0
( 2sin x - 1 ) ( cos x - 1 ) = 0
sin x =1 / 2 or cos x = 1
....
x = 咩野 , 自己計到啦 !
參考: 自己
2008-02-11 1:56 am
sin 2x - 2sin x - cos x +1=0
2sinx (cosx -1)-(cos x -1) =0
(2sinx-1)(cos x -1)=0
sinx=1/2 or cosx=1
x=n(pi)+(-1)^n (pi)/6 or x=2n(pi) , where n is any integer
2sinx (cosx -1)-(cos x -1) =0
(2sinx-1)(cos x -1)=0
sinx=1/2 or cosx=1
x=n(pi)+(-1)^n (pi)/6 or x=2n(pi) , where n is any integer
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