h(x)= (log2 x)^x
Find the derivative
Find the derivative
2008-02-10 7:17 am
回答 (1)
2008-02-11 2:16 am
✔ 最佳答案
take logarithm to both sidelog h(x) = xlog (log 2x)
differentiate both w.r.t x
1/h(x) * h'(x) = log(log2x)+x*1/(log2x)*1/(2x)*2
1/h(x) * h'(x) =log(log2x)+1/(log2x)
h'(x)= {log(log2x)+1/(log2x)}*{(log2 x)^x}
收錄日期: 2021-04-13 15:06:42
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20080209000051KK03048