If x-y = 10, y = 2z, y = 2z, and z = 3, what is the value of x?

y = 6
x - 6 = 10
x = 16
OPTION e.

y = 2(3)
y = 6

So x-y = 10
x = y+10
x = 10+6
x=16

e the answer

x-y=10, but, y =2z => x-2z=10 where z=3

x - (2x3) =10=> x-6=10, x=10+6.

x=16. the answer is the option (e)

the answer is e. 16
z=3 (substitute this into y=2z)
y=2(3)
y=6
now substitute y=6 into x-y=10
x-(6)=10
add six on both sides
x=16

z = 3
y = 6
x-y = 10
x - 6 = 10
x = 16

answer :e

x=16

well if z=3 then y=6 so x-6=10 therefore x=16 (e)

Sub in 2z for y

x-(2z)=10
Sub in 3 for z
x-(2*3)=10
Solve
x-6=10
x=16

y = 2z
y = 2 * 3
y = 6

x - y = 10
x - 6 = 10
x = 10 + 6
x = 16

16

x-y=10, y=2z, z=3

y=2(3)
y=6

x-(6)=10
+6 +6
x=16 (E)