factor completly: 4x^2+44x+96?

[06]
4x^2+44x+96
=4(x^2+11x+24)
=4(x^2+3x+8x+24)
=4{x(x+3)+8(x+3)}
=4(x+3)(x+8)

I take it that you recommend 72x^2 there. you are able to take out a 4 as a element of the finished equation so that you get: 4(18x^2 + 11x - 24) Factorising, you get 4(2x + 3)(9x - 8) As for what can sum as a lot as 40 4 and has a made up of -ninety six, it would not truly artwork the following because there's a great determination in the front of x^2.

4 (x ² + 11x + 24)
4 (x + 8) (x + 3)

4x^2 + 44x + 96
= (4x + 12)(x + 8)
= 4(x + 3)(x + 8)

4(x+3)(x+8)

4 ( x + 3) ( x+ 8)

First get rid of the 4 so divide by it.

4 (x^2 + 11x + 24)

Factor out the equation and you have your answer

=4x² + 11x + 24)
=4(x + 8)(x + 3)

common factor:

4 (x^2 + 11x + 24)

4 (x+3)(x+8)

4x² + 44x + 96

4(x² + 11x + 24)

4(x + 8)(x + 3)

4(x^2 + 11x + 24)
4(x + 3)(x + 8).