Find the term as indicated in the following:
{(x^3) - [1/(2x)]}^16 ,, the constant term.
thanks
binomial theorem @ amaths
2008-02-09 1:09 am
回答 (1)
2008-02-09 1:21 am
✔ 最佳答案
The general term of binomial coefficient isnCr[a^(n-r)b^r]
Now n=16,a=x^3,b=-1/2x
The genenral term is
16Cr[x^3(16-r)(-2x)^(-r)]
=(-2)^(-r)16Cr[x^(48-4r)]
So to find the constant term
Let 48-4r=0, r=12
T he constant term
=(-2)^(-12)16C12
=1820/4096
=455/1024
2008-02-08 17:22:34 補充：
If the answer is wrong, please let me know !
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