MATH...

2008-02-08 1:56 am

分解為因式
*請列式(^代表次方):

1a)6a^2-25ab+4b^2
=(6a-b)(a-4b)

1b)利用a部結果將6a^2-25ab+4b^2-5a+20b分解為因式
=?

回答 (4)

2008-02-08 2:04 am

✔ 最佳答案

6a^2-25ab+4b^2-5a+20b
=(6a-b)(a-4b)-5(a-4b)
=(a-4b)(6a-b-5)

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2008-02-08 3:11 am

6a^2-25ab+4b^2-5a+20b

=(6a-b)(a-4b)-5(a-4b)

=(a-4b)(6a-b-5)

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2008-02-08 2:29 am

6a^2-25ab+4b^2-5a+20b

=(6a-b)(a-4b)-5(a-4b)

=(6a-b)(a-4b)-5a+20b

=(a-4b)(6a-b-5)

參考: ME

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2008-02-08 2:09 am

要用cross method:
1a) 6a^2-25ab+4b^2
=6a 4b
X
1a 1b
------------------------
= 24ab+1ab
=(6a-b)(a-4b)

I only know question a) ...I hope i can help u

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