分解為因式
*請列式(^代表次方):
1a)6a^2-25ab+4b^2
=(6a-b)(a-4b)
1b)利用a部結果將6a^2-25ab+4b^2-5a+20b分解為因式
=?
MATH...
2008-02-08 1:56 am
回答 (4)
2008-02-08 2:04 am
✔ 最佳答案
6a^2-25ab+4b^2-5a+20b=(6a-b)(a-4b)-5(a-4b)
=(a-4b)(6a-b-5)
2008-02-08 3:11 am
6a^2-25ab+4b^2-5a+20b
=(6a-b)(a-4b)-5(a-4b)
=(a-4b)(6a-b-5)
=(6a-b)(a-4b)-5(a-4b)
=(a-4b)(6a-b-5)
2008-02-08 2:29 am
6a^2-25ab+4b^2-5a+20b
=(6a-b)(a-4b)-5(a-4b)
=(6a-b)(a-4b)-5a+20b
=(a-4b)(6a-b-5)
=(6a-b)(a-4b)-5(a-4b)
=(6a-b)(a-4b)-5a+20b
=(a-4b)(6a-b-5)
參考: ME
2008-02-08 2:09 am
要用cross method:
1a) 6a^2-25ab+4b^2
=6a 4b
X
1a 1b
------------------------
= 24ab+1ab
=(6a-b)(a-4b)
I only know question a) ...I hope i can help u
1a) 6a^2-25ab+4b^2
=6a 4b
X
1a 1b
------------------------
= 24ab+1ab
=(6a-b)(a-4b)
I only know question a) ...I hope i can help u
收錄日期: 2021-04-25 17:20:49
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