5(2x-1)-2(3x)=1?

2008-02-06 10:19 am
How do you solve..????????
5(2x-1)-2(3x)=1

what are the steps to sloving this equation???

Thanks.
更新1:

Explain in details what are the steps??

回答 (12)

2008-02-06 10:29 am
✔ 最佳答案
10x - 5 - 6x = 1
4x = 6
y = 3/2
2008-02-06 10:24 am
10x-5 - 6x =1
4x -5 =1
4x=6
x=4/6
x=2/3
2008-02-06 10:23 am
5(2x - 1) - 2(3x) = 1
5*2x - 5*1 - 2*3x = 1 (expansion)
10x - 5 - 6x = 1
4x - 5 = 1
4x = 1 + 5
4x = 6
x = 6/4
x = 3/2
x = 1 1/2
2008-02-06 10:28 am
5 (2x-1)
10x-5

-2 (3x)
-6x=1

10x-6x-5=1
4x=6

x=6/4 which is 3/2
2008-02-06 10:25 am
5(2x-1)-2(3x)=1
or, 10x - 5 - 6x = 1
or, 4x = 6
or, x = 6/4
or x = 3/2
Hence x = 3/2
2008-02-06 10:22 am
x = 3/2

5(2x-1)-2(3x)=1
10x - 5 - 6x = 1
4x = 6
x = 3/2
2008-02-06 10:29 am
5(2x-1)-2(3x)=1
= 10x-5-6x=1
= 10x-6x=1+5
= 4x=6
= x=6/4
= x=3/2
2008-02-06 10:28 am
5(2x-1)-2(3x)=1
10x -5 - 6x = 1
4x = 6 ->divide by 4
x = 3/2
x = 1,5
2008-02-06 10:22 am
answer = 10x - 5 -6x

which is the same as 4x-5
2008-02-06 10:42 am
Use this memory tool to help: Please Excuse my dear Aunt Salley. It means Parenthasis, Exponents, Multiplication and Divison, and then Addition and Substration.

Distribute your 5 and -2 accordingly. That is, 5 times 2x and 5 times -1. That should equal 10x-5. Now multiply -2 by 3x to get -6x. Your end result should be 10x-5-6x=1 *It is acceptable to multiply/divide unlike terms, but not to add/subtract unlike terms. Ex: -2 times 3x[acceptable], -2 plus 3x [unacceptable].* Now, since you can add/substract in any order, subtract 6x from the 10x to get 4x-5=1. Add five to both sides; 4x=6. Then divide both sides by 4; x=1.5 or x=1 1/2.

On paper it should look like this:
5(2x-1)-2(3x)=1
10x-5-6x=1
4x-5=1
4x=6
x=1.5 or 1 1/2

To conferm (if you use a graphing calculator) 5(2x-1)-2(3x) in Y1 and 1 in Y2. Find the intersection which should have an x value of 1.5.

Feel free to message me if you ever need more help. And if you do use either a TI-83 or 84, I have some nifty programs you may find useful.


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