Objective Function... Need help~

2008-02-06 11:26 pm
I have read my textbook N times... but I still have no idea how to draw the Objective Function graph...

For example:
z=125x+200y, where
x (less than) 450;
y (less than) 200;
600x + 900y (less than) 360000

I can graph the first two, for sure...
but what about the last one? How do I graph it?

As I know, 600x + 900y means the slope is 2/3.
But what about the 360000?

Please help... lots of questions still waiting for me...!
Thank you.
更新1:

So... what is the x-int and y-int ar? I do not know how to draw 600x + 900y (less than) 360000. Thank you.

回答 (1)

2008-02-06 11:46 pm
✔ 最佳答案
600x + 900y <= 360000 等價
6x+9y<=3600 等價
2x+3y<=1200
其實即是先畫一條2x+3y=1200的線
然後代(0,0)入去2x+3y=0<1200
所以只需將2x+3y=1200以下的部份用顏色塗上便行﹐如下圖所示

圖片參考:http://content.answers.com/main/content/wp/en/thumb/2/2d/240px-Linear_programming_example_graph.png



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