中二數學....急急急急急 !!!!!!!!!!!!thx

3x-1=4(y+1)
7(2x+3)=6y
3x-1 = 4y+4...(1)
14x+21 = 6y...(2)
from (2),
y = (14x+21)/6...(3)
sub. (3) into (1),
3x-1 = 4[(14x+21)/6]+4
9x-3 = 2(14x+21)+12
9x-3 = 28x+42 +12
-19x = 57
x = -3
sub. x = -3 into (2),
14(-3)+21 = 6y
-21 = 6y
y = -3.5
therefore the solution is x = -3, y = -3.5 //

3x = 4y + 4 +1
x = 4y/3 + 5/3 -- (1)
Sub (1) into 7(2x+3) = 6y

14 (4y/3 + 5/3) + 21 = 6y
56y/3 + 70/3 + 21 = 6y
(56/3 - 6)y = -70/3 - 21
y = -3.5

x = -3

3x-1=4(y+1) 3x-1=4y+1______(1)
7(2x+3)=6y 14x+21=6y_______(2)
From(1):3x-1=4y+1
3x=4y+1+1
3x=4y+2
x=(4y+2)/3___________(3)
Sub. (3) into (2)
14(4y+2)/3+21=6y
56y+28+21=6y
56y-6y=-28-21
50y=-49
y=-0.98
Sub.y=-0.98 into (3)
x=(4y+2)/3
x=(4x0.98+2)/3
x=5.92/3