Maths 題: Expand each of the following
(a) -1/2a(6a-2)
(b) (-a4b2+a3b2) 除a2b
(THX!!!)
Expand each of the following......(THX!!!)
2008-02-06 3:00 am
回答 (2)
2008-02-06 4:01 am
2008-02-06 4:09 am
(a) -1/2a(6a-2)
= (-0.5a X 6a)-(-0.5a X -2)
= -3a ^2- 1a
= -(3a^2+1a)
(b) (-a4b2+a3b2)/a2b
= -4a2b+3a2b /2ab
= -8ab+6ab/2ab
= -2ab/2ab
= -1
= (-0.5a X 6a)-(-0.5a X -2)
= -3a ^2- 1a
= -(3a^2+1a)
(b) (-a4b2+a3b2)/a2b
= -4a2b+3a2b /2ab
= -8ab+6ab/2ab
= -2ab/2ab
= -1
參考: I am not sure i am right(from my own knowledge)
收錄日期: 2021-04-25 17:20:10
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