how do you factor 100x^4-9?
回答 (11)
2008-02-04 3:01 pm
✔ 最佳答案
100x^4-9this can be written as
({10x^2}^2-{3}^2)
this is of the form (a^2-b^2)
(a^2-b^2)=(a+b)(a-b), where a=10x^2 & b=3
now substitute tis in the formula
({10x^2}^2-{3}^2)=(10x^2-3)(10x^2+3)
2008-02-04 10:58 pm
Difference of squares:
100x^4 is 10x^2 squared
9 is 3 squared
so it factors to
(10x^2 + 3)(10x^2 -3)
100x^4 is 10x^2 squared
9 is 3 squared
so it factors to
(10x^2 + 3)(10x^2 -3)
2008-02-04 11:53 pm
This is the difference of two squares
a^2 - b^2
which factors as
(a+b)(a-b)
a^2 = 100x^4 = (10x^2)^2 b^2 = 9
Therefore, the result is
(10x^2+3)(10x^2-3)
a^2 - b^2
which factors as
(a+b)(a-b)
a^2 = 100x^4 = (10x^2)^2 b^2 = 9
Therefore, the result is
(10x^2+3)(10x^2-3)
參考: Longtime college math teacher
2008-02-04 11:29 pm
100x^4-9=(10x²-3)·(10x²+3) =
(â10 ·x - â3) · (â10 ·x + â3)· (10x²+3)
(â10 ·x - â3) · (â10 ·x + â3)· (10x²+3)
2008-02-04 11:16 pm
a^2-b^2=(a-b)(a+b)
100x^4-9 = (10x^2)^2-3^2
=(10x^2-3)(10x^2+3)
100x^4-9 = (10x^2)^2-3^2
=(10x^2-3)(10x^2+3)
2008-02-04 11:03 pm
100x^4 - 9
= (10x^2 + 3)(10x^2 - 3)
= (10x^2 + 3)(10x^2 - 3)
2008-02-04 11:03 pm
100x^4 -
difference of squares.
(10x^2 - 3) (10x^2 + 3)
this is factored completely relative to the integers.
:)
difference of squares.
(10x^2 - 3) (10x^2 + 3)
this is factored completely relative to the integers.
:)
2008-02-04 11:02 pm
100x^4-9=(10x²-3)·(10x²+3) =
(â10 ·x - â3) · (â10 ·x + â3)· (10x²+3)
Saludos.
(â10 ·x - â3) · (â10 ·x + â3)· (10x²+3)
Saludos.
2008-02-04 10:59 pm
Difference of two squares.
100x^4-9 = 10²(x²)² - 3² = [10x²]² - 3²
==> (10x² + 3)(10x² - 3)
:)
100x^4-9 = 10²(x²)² - 3² = [10x²]² - 3²
==> (10x² + 3)(10x² - 3)
:)
2008-02-06 12:15 am
(10 x ² - 3)(10 x ² + 3)
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