chemistry question

2008-02-04 11:37 pm

In an experiment, 21.1 mL of 0.270 M barium hydroxide was mixed with 25.0 mL of 0.330 M aluminum sulfate. Based upon this reaction, you will be determining
Write the complete ionic reaction that describes the reaction, including states, between barium hydroxide and aluminum sulfate.
The concentration of the sulfate anion is ?M and the concentration of the Al3+ cation is ?M.

回答 (1)

魏王將張遼

2008-02-05 12:15 am

✔ 最佳答案

Equations:
Al3+(aq) + 3OH-(aq) → Al(OH)3(s)
Ba2+(aq) + SO42-(aq) → BaSO4(s)
Originally, no. of moles of those ions are:
Al3+(aq) = 2 × 0.33 × 0.025 = 0.0165
SO42-(aq) = 3 × 0.33 × 0.025 = 0.02475
Ba2+(aq) = 0.27 × 0.0211 = 0.005697
OH-(aq) = 0.27 × 0.0211 = 0.005697
So, for Ba2+ and SO42-, the latter is in excess with 0.02475 - 0.005697 = 0.019053 moles remained.
For Al3+ and OH-, the former is in excess with 0.0165 - 0.005697/3 = 0.014601 moles remained.
Now, resulting solution volume = 46.1 mL and therefore:
[Al3+(aq)] = 0.014601/0.0461 = 0.317 M
[SO42-(aq)] = 0.019053/0.0461 = 0.413 M

參考: My chemical knowledge

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