Factorise this question
(x sq.-x)sq.-4(x sq.-x)-12
(sq.=二次)
Maths question
2008-02-03 6:24 am
回答 (5)
2008-02-03 8:30 pm
✔ 最佳答案
(x^2 - x)^2 - 4(x^2 - x) - 12= (x^2 - x - 6)(x^2 - x + 2)
= (x - 3)(x + 2)(x^2 - x+ 2)
參考: me
2008-02-05 6:29 am
(x^2 - x)^2 - 4(x^2 -x) - 12
=(x^2 - x - 6)(x^2 - x + 2) as -6(x^2 - x) + 2(x^2 - x) = -4(x^2 - x), -6 x 2 = -12
=(x - 3)(x +2)(x^2 - x + 2)
=(x^2 - x - 6)(x^2 - x + 2) as -6(x^2 - x) + 2(x^2 - x) = -4(x^2 - x), -6 x 2 = -12
=(x - 3)(x +2)(x^2 - x + 2)
2008-02-03 7:07 am
(x^2-x)^2-4(x^2-x)-12
=(x^2-x)(x^2-x)-4x^2+4x-12
=(x^2)(x^2)+(-x)(x^2)+(x^2)(-x)+(-x)(-x)-4x^2+4x-12
=x^4-x^3-x^3+x^2-4x^2+4x-12
=x^4-2x^3-3x^2+4x-12
=x(1^4-2x^2-3x+4-12)
P.S:^等於次方
x^2=2次方
=(x^2-x)(x^2-x)-4x^2+4x-12
=(x^2)(x^2)+(-x)(x^2)+(x^2)(-x)+(-x)(-x)-4x^2+4x-12
=x^4-x^3-x^3+x^2-4x^2+4x-12
=x^4-2x^3-3x^2+4x-12
=x(1^4-2x^2-3x+4-12)
P.S:^等於次方
x^2=2次方
參考: 我家姐
2008-02-03 6:36 am
Let y = (x sq.-x)
ysq.-4y - 12
= (y -6)(y+2)
(x sq.-x -6) (x sq.-x +2)
= (x - 3)(x + 2) (x sq.-x +2)
ysq.-4y - 12
= (y -6)(y+2)
(x sq.-x -6) (x sq.-x +2)
= (x - 3)(x + 2) (x sq.-x +2)
2008-02-03 6:36 am
(x^2-x)^2-4(x^2-x)-12
可以Let y be x^2-x
y^2-4y-12
=(y+2)(y-6)
=(x^2-x+2)(x^2-x-6)
=(x^2-x+2)(x+2)(x-3)
PS.我唔知你題數係咪有D問題，x^2-x+2 Factorise唔到，好似有D怪咁
可以Let y be x^2-x
y^2-4y-12
=(y+2)(y-6)
=(x^2-x+2)(x^2-x-6)
=(x^2-x+2)(x+2)(x-3)
PS.我唔知你題數係咪有D問題，x^2-x+2 Factorise唔到，好似有D怪咁
收錄日期: 2021-04-13 15:04:24
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