Give the complete factorization for the polynomial. 3x^2 - 6x - 240?

2008-02-01 4:27 pm
2. Give the complete factorization for the polynomial.
25a^2 - 100
3. Give the complete factorization for the polynomial.
10x - 3 - 3x^2
4. Write the complete factorization for the polynomial. -7y^2 + 7y + 84, the common coefficient is?
5. Give the complete factorization for the polynomial. 35d + 5d^2 - 30
Thank you.

回答 (6)

2008-02-01 4:43 pm
✔ 最佳答案
[05]
1) 3x^2-6x-240
=3(x^2-2x-80)
=3(x^2+8x-10x-80)
=3{x(x+8)-10(x+8)}
=3(x+8)(x-10)
2)25a^2-100
=(5a)^2-(10)^2
=(5a+10)(5a-10)
You can also do this in the following way
25(a^2-4)
=25{(a)^2-(2)^2}
=25(a+2)(a-2)
3)10x-3-3x^2
=-3x^2+10x-3
=-(3x^2-10x+3)
= -(3x^2-x-9x+3)
= -{x(3x-1)-3(3x-1)}
=-(3x-1)(x-3)
4)-7y^2+7y+84
= -7(y^2-y-12)
= -7(y^2+3y-4y-12)
= -7{y(y+3)-4(y+3)}
= -7(y+3)(y-4)
5)35d+5d^2-30
=5d^2+35d-30
=5(d^2+7d-6)
There is some mistake in the problem.I think it may be -35d+5d^2+30
-35d+5d^2+30
=5d^2-35d+30
=5(d^2-7d+6)
=5(d-1)(d-6)
2016-10-16 6:15 pm
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2008-02-01 5:11 pm
I'm pretty sure that the 1st one cannot be solved. I tried it myself. Sorry! I'll try the other ones later. I have to do some work of my own
2008-02-01 4:52 pm
1)
3x^2 - 6x - 240
= (3x - 30)(x + 8)

2)
25a^2 - 100
= 25(a^2 - 4)

3)
10x - 3 - 3x^2
= 3x^2 - 10x + 3
= (3x - 1)(x - 3)

4)
-7y^2 + 7y + 84
= (-7y + 28)(y + 3)

5)
35d + 5d^2 - 30
= 5d^2 + 35d - 30
= 5(d^2 + 7d - 6)
2008-02-01 4:43 pm
3x^2-6x-240
3(x^2-2x-120)
3(x^2-12x+10x-120)
x^2-12x+10x-120 = x(x-12)+10(x-12)
(x-12)(x+10)
Multiply by 3
3(x-12)(x+10)
2008-02-01 4:36 pm
1. (3x + 24)(x - 10)
2. (5a - 10)(5a + 10)
3. (3x - 1)(-x + 3)
4. (7y + 21)(-y + 4)
5. (5d - 5)(d + 6) ----> i think something is wrong in your equation..... should it be 25d instead?


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