SOLVE : x^2 - 12 = 4x?

x ² - 4 x - 12 = 0
(x - 6) (x + 2) = 0
x = 6 , x = - 2

x² - 12 = 4x

Transpose 4x

x² - 4x - 12 = 4x - 4x

x² - 4x - 12 = 0

The middle term is - 4x

Find the sum of the middle term

The first term x² = 1

Multiply the first term 1 times the last term - 12 equals - 12 and factor

The factors of - 12 are

1 x - 12
2 x - 6. . .←. .use these factors
3 x - 4

- 6x and + 2x satisfy the sum of the middle term

insert - 6x and + 2x into the equation

x² - 4x - 12 = 0

x² - 6x + 2x - 12 = 0

Group factor

(x² - 6x) + (2x - 12) = 0

x(x - 6) + 2(x - 6) = 0

(x + 2)(x - 6) = 0

- - - - - - -

Roots

x + 2 = 0

Transpose 2

x + 2 - 2 = 0 - 2

x = - 2

Insert the x value into the equation

- - - - - - - -

Roots

x - 6 = 0

Transpose 6

x - 6 + 6 = 0 + 6

x = 6

Insert the x value into the equation

- - - - - - - -

Check

x = -2

x² - 4x - 12 = 0

(-2)² - 4(- 2) - 12 = 0

4 - (- 8) - 12 = 0

4 + 8 - 12 = 0

12 - 12 = 0

0 = 0
- - - - - - - - -

Check

x = 6

x² - 4x - 12 = 0

(6)² - 4(6) - 12 = 0

36 - 24 - 12 = 0

12 - 12 = 0

0 = 0

- - - - - - - - -

Ths solution for equation x² - 4x - 12 = 0

are x = - 2 and x = 6

- - - - - - - - -s-

Subtract 4x from both sides to set = 0.

x^2 - 4x - 12 = 0. Factor.
(x-6)(x+2) = 0.
x = 6.
x = -2.

x²-4x-12=0

(x+2)(x-6)=0

x=-2 or x=6

Begin by writing the equation in the canonical form (a * x ** 2 + b * x + c = 0):
x ** 2 - 4 * x - 12 = 0
Now try to factorise ..... in this case, it works .....
(x - 6) * (x + 2) = 0
therefore x = 6 or -2.

x^2 - 12 = 4x
x^2 - 12 - 4x = 0
x^2 - 4x - 12 = 0
(x - 6)(x + 2) = 0
x = 6 or -2

X = 6

x^2 -12 + 4x
x^2 - 4x -12 = 0

now you split the middle term such that the two split nos add up to the middle term and its product is equal to the product of the first term and the constant.

x^2 -6x + 2x - 12 [ -6x + 2x = -4x; (-6x)(2x) = (-12)(x^2); ]

now take x common from the first two terms and 2 from the next two terms.

x(x - 6) +2(x - 6) = 0

now (x - 6) is common in both the terms.
so take it common

(x - 6)(x + 2) = 0

so either (x-6) is 0 or (x+2) is 0.

if x-6 is 0
then x + 2 = 0
x = -2

if x + 2 is 0
then x - 6 = 0
x = 6

therefore x = 6 (or) -2

x^2 - 12 = 4x <=>
x^2- 4x-12 = 0 <=>
Either x = (4+8)/2 = 6
or x= (4-8)/2 = -2

EDIT: To whoever gave the thumbs down to everyone: Are you stating that all the answers are wrong?Can't you see you are confusing the asker by doing so? Or you think this is too simple for your clever mind??? [no offence meant]

X 2 4x 12