f.1maths

2008-01-29 8:35 pm

7[2(x-3)+x]=4[1-3(x+2)]
唔該有step

回答 (6)

2008-01-29 8:51 pm

✔ 最佳答案

7[2(x-3)+x]=4[1-3(x+2)]
7[2x-6+x]=4[1-3x-6]
7[3x-6]=4[-3x-5]
21x-42= -12x-20
21x+12x=-20+42
33x=22
x=22/33
x=2/3

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2008-01-29 11:03 pm

7(2x-6+x) = 4(1-3x-6)
7(3x-6) = 4(-3x-5)
21x-42 = -12x-20
33x = 22
x = 22/33 = 2/3

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2008-01-29 8:50 pm

7[2(x-3)+x]=4[1-3(x+2)]

7(2x-6+x)=4(1-3x-6)

14x-42+7x=4-12x-24
21x-42=-12x-20

33x=22

x=2/3

x=0.67

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2008-01-29 8:49 pm

7[2x-6+x] = 4[1-3x-6]

7[3x-6] = 4[-3x-5]

21x-42 = -12x -20

33x = 22

x = 2/3

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2008-01-29 8:48 pm

7[2(x-3)+x]=4[1-3(x+2)]

7[2x-6+x]=4[1-3x-6]

21x-42= -20-12x

33x=22

x=2/3

你自己也試試吧。

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2008-01-29 8:45 pm

7[2(x-3)+x]=4[1-3(x+2)]
7(2x-6+x) =4(1-3x-6)
14x-42+7x=4-12x-24
14x+12x+7x =4-24+42
33x = 22
x= 2/3

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