x/x=份數
Find the values
2(x+30) - (5-3X)≡Ax+B
Expand
(x+a)(x-a)(x二次+a二次)
Determine
2-3 /3 - 3x-4/4 = - (x/12)
f.2maths 快入
2008-01-29 4:51 am
回答 (1)
2008-01-29 5:37 am
✔ 最佳答案
Find the values2(x+30) - (5-3X)≡Ax+B
2x+60-5+3x≡Ax+B
5x+55≡Ax+B
A=5,B=55
Expand
(x+a)(x-a)(x二次+a二次)
=(x二次-a二次)(x二次+a二次)
=(x四次-a四次)
[P.S. (a+b)(a-b)=(a二次-b二次)]
Determine
(2-3x) /3 - (3x-4)/4
=[4(2-3x)/12]-[3(3x-4)/12]
=(8-12x-9x+12)/12
=(20-21x)/12
Therefore,2-3 /3 - 3x-4/4 =/= - (x/12)
收錄日期: 2021-04-25 17:18:08
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20080128000051KK03076