Find the values of B and 0<= B <= 360 (with general solution)
a) 4 (sinB)^2 - 3sinBcosB - (cosB)^2 = 0
b) 3 (tanB)^2 -16(sinB)^2 +3 = 0
c) 2(sinB)^2 - cosB - 1 = 0
Trigonometry
2008-01-28 6:06 am
回答 (2)
2008-01-28 7:25 am
✔ 最佳答案
As follows:圖片參考：http://i238.photobucket.com/albums/ff245/chocolate328154/Maths137.jpg?t=1201447511
參考: My Maths Knowledge
2008-01-30 4:59 am
正評都不夠嘛！
收錄日期: 2021-04-14 19:43:36
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20080127000051KK03811