http://xbd.xanga.com/0a1c367646430170235842/s129131929.png
在圖中,AEC , BFC和DFE都是直線。BD=EC,BD//AC及AB//ED。證明BE是三角形ABC中由B至AC的中線。
仲有牙!!!我而定讀F.3,教緊演繹幾何簡介(二),但係真係好差lo~
就好似上面果題敢,我唔識點樣證明牙...
而家仲要加多一個證明,就係三角形內一些特殊的線,我想知道要點樣證明嫁
有咩步驟or秘訣牙!!!><
懇請各位幫幫忙,我maths唔可以再係禁差嫁la ='(
三角形內特殊線的證明~!!(急)
2008-01-26 2:10 am
回答 (2)
2008-01-26 3:01 am
✔ 最佳答案
As follows:圖片參考：http://xbd.xanga.com/0a1c367646430170235842/s129131929.png
Since BD // AC and AB // ED, ABDE is a // gram ( by definition ).
BD = AE ( prop. of // gram )
BD = EC ( given )
So AE = EC and hence BE is a median of triangle ABC.
參考: My Maths Knowledge
2008-02-04 4:54 am
AE = EC
收錄日期: 2021-04-11 00:29:05
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20080125000051KK02089